What is the tangent of f(x)=(3x)/((x+1)^2),(0,0) ?

The tangent of f(x)=(3x)/((x+1)^2),(0,0) is y=3x

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tangent of f(x)=(3x)/((x+1)^2),(0,0)

tangent of

f (x) = \frac{3 x}{( x + 1 ) ^{2}}, (0, 0)

y = 3 x

Solution steps

Find the slope of

f (x) = \frac{3 x}{( x + 1 ) ^{2}} : \frac{df ( x )}{d x} = \frac{3 ( 1 - x )}{( x + 1 ) ^{3}}

Compute the slope of

f (x) = \frac{3 x}{( x + 1 ) ^{2}}

(0, 0) : m = 3

Find the line with slope m=

3

and passing through

(0, 0) : y = 3 x

y = 3 x

\frac{d}{d x} ((3 x^{2} + 19 x - 7) (14 x^{3} + 12 x))

x \to 0 lim (\frac{1}{x - 2})

x^{2} y^{^{'}} - x y - x^{3} sin (x) = 0

\frac{d}{d x} (\frac{3 π}{4 x ^{5}})

\int \frac{12}{1 - cos ( 6 x )} d x

What is the tangent of f(x)=(3x)/((x+1)^2),(0,0) ?
The tangent of f(x)=(3x)/((x+1)^2),(0,0) is y=3x