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Popular >

y^'+2y=6,y(0)=0

Solution

y^{^{'}} + 2 y = 6, y (0) = 0

Solution

y = - 3 e^{- 2 t} + 3

Solution steps

y^{'} (t) + 2 y = 6

Solve separable ODE:

y = - 3 e^{- 2 t} + 3

y = - 3 e^{- 2 t} + 3

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Frequently Asked Questions (FAQ)

What is the solution for y^'+2y=6,y(0)=0 ?
The solution for y^'+2y=6,y(0)=0 is y=-3e^{-2t}+3