What is inverse oflaplace-1/s ?

The answer to inverse oflaplace-1/s is -\H(t)

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inverse oflaplace-1/s

inverse laplace

- \frac{1}{s}

- H (t)

Solution steps

L^{- 1} {- \frac{1}{s}}

Use the constant multiplication property of Inverse Laplace Transform:

For function

f (t)

and constant

a : L^{- 1} {a \cdot f (t)} = a \cdot L^{- 1} {f (t)}

= - L^{- 1} {\frac{1}{s}}

L^{- 1} {\frac{1}{s}} : H (t)

= - H (t)

- \frac{e ^{- π s}}{s ^{2} + 1}

(1950, 38300), (2000, 82500)

\int 7 sin (t) d t

f^{^{'}} (x) = x^{2} - 5

\int x sin (x) d x