What is the integral of 30(16-x^2) ?

The integral of 30(16-x^2) is 30(16x-(x^3)/3)+C

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integral of 30(16-x^2)

\int 30 (16 - x^{2}) d x

30 (16 x - \frac{x ^{3}}{3}) + C

Solution steps

\int 30 (16 - x^{2}) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 30 \cdot \int 16 - x^{2} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= 30 (\int 16 d x - \int x^{2} d x)

\int 16 d x = 16 x

\int x^{2} d x = \frac{x ^{3}}{3}

= 30 (16 x - \frac{x ^{3}}{3})

Add a constant to the solution

= 30 (16 x - \frac{x ^{3}}{3}) + C

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What is the integral of 30(16-x^2) ?
The integral of 30(16-x^2) is 30(16x-(x^3)/3)+C