What is (\partial)/(\partial x)(cos(z)+xy^2) ?

The answer to (\partial)/(\partial x)(cos(z)+xy^2) is y^2

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(\partial)/(\partial x)(cos(z)+xy^2)

\frac{\partial}{\partial x} (cos (z) + x y^{2})

y^{2}

Solution steps

\frac{\partial}{\partial x} (cos (z) + x y^{2})

Treat

z, y

as constants

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (cos (z)) + \frac{\partial}{\partial x} (x y^{2})

\frac{\partial}{\partial x} (cos (z)) = 0

\frac{\partial}{\partial x} (x y^{2}) = y^{2}

= 0 + y^{2}

Simplify

= y^{2}

\int_{0}^{7} x^{3} e^{x} d x

f (x) = \frac{1}{4 x ^{\frac{3}{2}}}, at x = 4

\frac{d y}{d x} = 6 x^{2} y

\int e^{r^{2}} d r

x \to 0 lim (\frac{ln ( 1 )}{x})

What is (\partial)/(\partial x)(cos(z)+xy^2) ?
The answer to (\partial)/(\partial x)(cos(z)+xy^2) is y^2