What is (\partial)/(\partial m)(mx+b) ?

The answer to (\partial)/(\partial m)(mx+b) is x

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(\partial)/(\partial m)(mx+b)

\frac{\partial}{\partial m} (m x + b)

x

Solution steps

\frac{\partial}{\partial m} (m x + b)

Treat

x, b

as constants

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial m} (m x) + \frac{\partial}{\partial m} (b)

\frac{\partial}{\partial m} (m x) = x

\frac{\partial}{\partial m} (b) = 0

= x + 0

Simplify

= x

\int (1 - \frac{1}{x})^{2} d x

n = 1 \sum \infty \frac{3 ^{n}}{4 ^{n}}

\int_{9}^{16} x d x

\frac{d}{d x} (sin (\frac{π x}{8}))

n = 0 \sum \infty \frac{1}{n ( ln ( n ) )}

What is (\partial)/(\partial m)(mx+b) ?
The answer to (\partial)/(\partial m)(mx+b) is x