What is the integral of 4x^3-2x^2 ?

The integral of 4x^3-2x^2 is x^4-(2x^3)/3+C

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integral of 4x^3-2x^2

\int 4 x^{3} - 2 x^{2} d x

x^{4} - \frac{2 x ^{3}}{3} + C

Solution steps

\int 4 x^{3} - 2 x^{2} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 4 x^{3} d x - \int 2 x^{2} d x

\int 4 x^{3} d x = x^{4}

\int 2 x^{2} d x = \frac{2 x ^{3}}{3}

= x^{4} - \frac{2 x ^{3}}{3}

Add a constant to the solution

= x^{4} - \frac{2 x ^{3}}{3} + C

\int 6 x \cdot e^{x^{2} - 2} d x

\frac{d}{d z} (sin (z))

\int \frac{1}{- u ^{2} + b - a} d u

x \to \infty lim (\frac{x - x x}{2 x ^{\frac{3}{2}} + 3 x - 5})

9 x + 10