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Popular >

y^'+5xy=6x

Solution

y^{^{'}} + 5 x y = 6 x

Solution

y = \frac{e ^{\frac{- 5 x ^{2} + c _{1}}{2}}}{5} + \frac{6}{5}

Solution steps

y^{'} (x) + 5 x y = 6 x

Solve separable ODE:

y = \frac{e ^{\frac{- 5 x ^{2} + c _{1}}{2}}}{5} + \frac{6}{5}

y = \frac{e ^{\frac{- 5 x ^{2} + c _{1}}{2}}}{5} + \frac{6}{5}

Popular Examples

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y = 6 + 5 x^{2} + 2 x^{3}

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\int \frac{2 x}{x ^{4} + 16} d x

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x^2*y^'+(2-y)=0

x^{2} \cdot y^{^{'}} + (2 - y) = 0

(\partial)/(\partial x)((2x+3y)^{10})

\frac{\partial}{\partial x} ((2 x + 3 y)^{10})

Frequently Asked Questions (FAQ)

What is the solution for y^'+5xy=6x ?
The solution for y^'+5xy=6x is y=(e^{(-5x^2+c_{1})/2})/(5)+6/5