What is the derivative of 1/(t^4) ?

The derivative of 1/(t^4) is -4/(t^5)

What is the first derivative of 1/(t^4) ?

The first derivative of 1/(t^4) is -4/(t^5)

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derivative of

\frac{1}{t ^{4}}

- \frac{4}{t ^{5}}

Solution steps

\frac{d}{d t} (\frac{1}{t ^{4}})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= \frac{d}{d t} (t^{- 4})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= - 4 t^{- 4 - 1}

Simplify

- 4 t^{- 4 - 1} : - \frac{4}{t ^{5}}

= - \frac{4}{t ^{5}}

\int (sin (y) - y sin (x)) d x

\frac{\partial}{\partial t} (x + y sin (t))

\frac{d}{d x} (x^{2} + c^{2})

\frac{d}{d x} (\frac{2}{2 + x})

\frac{\partial}{\partial y} (3 x^{2} - 12 y)

What is the derivative of 1/(t^4) ?
The derivative of 1/(t^4) is -4/(t^5)
What is the first derivative of 1/(t^4) ?
The first derivative of 1/(t^4) is -4/(t^5)