What is the derivative of 2/(2+x) ?

The derivative of 2/(2+x) is -2/((2+x)^2)

What is the first derivative of 2/(2+x) ?

The first derivative of 2/(2+x) is -2/((2+x)^2)

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\frac{d}{d x} (\frac{2}{2 + x})

- \frac{2}{( 2 + x ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{2}{2 + x})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d x} (\frac{1}{2 + x})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= 2 \frac{d}{d x} ((2 + x)^{- 1})

Apply the chain rule:

- \frac{1}{( 2 + x ) ^{2}} \frac{d}{d x} (2 + x)

= - \frac{1}{( 2 + x ) ^{2}} \frac{d}{d x} (2 + x)

\frac{d}{d x} (2 + x) = 1

= 2 (- \frac{1}{( 2 + x ) ^{2}} \cdot 1)

Simplify

2 (- \frac{1}{( 2 + x ) ^{2}} \cdot 1) : - \frac{2}{( 2 + x ) ^{2}}

= - \frac{2}{( 2 + x ) ^{2}}

\frac{\partial}{\partial y} (3 x^{2} - 12 y)

y = (\frac{x + 1}{x - 1})^{2}, (3, 4)

f (x) = x^{9}, at x = - 1

\frac{d}{d x} (e^{2 x} n (3 x))

\frac{3}{8} π r^{3}

What is the derivative of 2/(2+x) ?
The derivative of 2/(2+x) is -2/((2+x)^2)
What is the first derivative of 2/(2+x) ?
The first derivative of 2/(2+x) is -2/((2+x)^2)