What is the derivative of 14e^{x^2}x ?

The derivative of 14e^{x^2}x is 14(2e^{x^2}x^2+e^{x^2})

What is the first derivative of 14e^{x^2}x ?

The first derivative of 14e^{x^2}x is 14(2e^{x^2}x^2+e^{x^2})

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derivative of

14 e^{x^{2}} x

14 (2 e^{x^{2}} x^{2} + e^{x^{2}})

Solution steps

\frac{d}{d x} (14 e^{x^{2}} x)

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 14 \frac{d}{d x} (e^{x^{2}} x)

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = e^{x^{2}}, g = x

= 14 (\frac{d}{d x} (e^{x^{2}}) x + \frac{d x}{d x} e^{x^{2}})

\frac{d}{d x} (e^{x^{2}}) = e^{x^{2}} \cdot 2 x

\frac{d x}{d x} = 1

= 14 (e^{x^{2}} \cdot 2 xx + 1 \cdot e^{x^{2}})

Simplify

14 (e^{x^{2}} \cdot 2 xx + 1 \cdot e^{x^{2}}) : 14 (2 e^{x^{2}} x^{2} + e^{x^{2}})

= 14 (2 e^{x^{2}} x^{2} + e^{x^{2}})

\frac{\partial}{\partial x} (ln (x^{2} + 2 y^{2}))

f (x) = x + cos (x)

\frac{d y}{d x}, x y = 10

\frac{\partial}{\partial x} (2 e^{x} - 4 x e^{y})

\int sec^{2} (x t a) n^{6} x d x

What is the derivative of 14e^{x^2}x ?
The derivative of 14e^{x^2}x is 14(2e^{x^2}x^2+e^{x^2})
What is the first derivative of 14e^{x^2}x ?
The first derivative of 14e^{x^2}x is 14(2e^{x^2}x^2+e^{x^2})