What is area f(x)=0.8x^2+4,g(x)=x,[-6,6] ?

The answer to area f(x)=0.8x^2+4,g(x)=x,[-6,6] is 163.2

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area f(x)=0.8x^2+4,g(x)=x,[-6,6]

area

f (x) = 0.8 x^{2} + 4, g (x) = x, [- 6, 6]

163.2

Solution steps

Apply the area formula:

\int_{- 6}^{6} 0.8 x^{2} + 4 - x d x

Solve

\int_{- 6}^{6} 0.8 x^{2} + 4 - x d x : 163.2

The area is:

= 163.2

\int \frac{u}{x} d x

y = sec^{2} (3 x)

\frac{d}{d y} (2 y - \frac{1}{x} + cos (3 x))

\int (x \cdot cos (5 x)) d x

e^{\frac{1}{x}} 0

What is area f(x)=0.8x^2+4,g(x)=x,[-6,6] ?
The answer to area f(x)=0.8x^2+4,g(x)=x,[-6,6] is 163.2