What is the f(x)= 1/(x^2+3) ?

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f(x)= 1/(x^2+3)

f (x) = \frac{1}{x ^{2} + 3}

Domain : - \infty < x < \infty

Range : 0 < f (x) \leq \frac{1}{3}

Y Intercepts : (0, \frac{1}{3})

Asymptotes : Horizontal y = 0

Extreme Points : Maximum (0, \frac{1}{3})

Interval Notation

Domain : (- \infty, \infty)

Range : (0, \frac{1}{3}]

Solution steps

Domain of

\frac{1}{x ^{2} + 3} : - \infty < x < \infty

Range of

\frac{1}{x ^{2} + 3} : 0 < f (x) \leq \frac{1}{3}

Axis interception points of

\frac{1}{x ^{2} + 3} :

Y Intercepts

: (0, \frac{1}{3})

Asymptotes of

\frac{1}{x ^{2} + 3} :

Horizontal

: y = 0

Extreme Points of

\frac{1}{x ^{2} + 3} :

Maximum

(0, \frac{1}{3})

\int_{0}^{1} \frac{1}{x ^{0.5} ln ( x )} d x

f (x) = tan (x), at x = π

\frac{d}{d x} (3^{2})

\int (\frac{5 x ^{3}}{2 x ^{2}}) d x

n = 0 \sum \infty \frac{1}{n + 8}