What is the solution for (dy}{dx}=\frac{-4sin(x)cos(x))/y ?

The solution for (dy}{dx}=\frac{-4sin(x)cos(x))/y is y=sqrt(2cos(2x)+c_{1)},y=-sqrt(2cos(2x)+c_{1)}

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(dy}{dx}=\frac{-4sin(x)cos(x))/y

\frac{d y}{d x} = \frac{- 4 sin ( x ) cos ( x )}{y}

y = 2 cos (2 x) + c_{1}, y = - 2 cos (2 x) + c_{1}

Solution steps

\frac{d y}{d x} = \frac{- 4 sin ( x ) cos ( x )}{y}

Solve separable ODE:

y = 2 cos (2 x) + c_{1}, y = - 2 cos (2 x) + c_{1}

y = 2 cos (2 x) + c_{1}, y = - 2 cos (2 x) + c_{1}

\int v (v^{2} + 2)^{2} d v

y^{^{''}} - 6 y^{^{'}} + 25 y = 0

\frac{\partial}{\partial y} (x sin (6 x^{2} y))

\int 24 sec^{5} (x) d x

\frac{d y}{d x} = \frac{( y ^{2} - 1 )}{( x ^{2} - 1 )}, y (0) = 1

What is the solution for (dy}{dx}=\frac{-4sin(x)cos(x))/y ?
The solution for (dy}{dx}=\frac{-4sin(x)cos(x))/y is y=sqrt(2cos(2x)+c_{1)},y=-sqrt(2cos(2x)+c_{1)}