What is the (dy)/(dx)=((y^2-1))/((x^2-1)),y(0)=1 ?

The (dy)/(dx)=((y^2-1))/((x^2-1)),y(0)=1 is 0

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(dy)/(dx)=((y^2-1))/((x^2-1)),y(0)=1

\frac{d y}{d x} = \frac{( y ^{2} - 1 )}{( x ^{2} - 1 )}, y (0) = 1

0

Solution steps

\frac{( y ^{2} - 1 )}{( x ^{2} - 1 )} = \frac{( y ^{2} - 1 )}{( x ^{2} - 1 )}

Constant function results in a constant

y (0) = 1

= \frac{1 ^{2} - 1}{x ^{2} - 1}

\frac{1 ^{2} - 1}{x ^{2} - 1} = 0

= 0

\frac{\partial}{\partial x} (4 x cos (x y))

f (x) = x^{2} + x + 2, 0, 12

\int \frac{4 + 7 x}{1 + x ^{2}} d x

\frac{d}{d x} (6 x (x^{2} - 1)^{2})

\int_{0}^{1} \frac{1}{16 - x ^{2}} d x

What is the (dy)/(dx)=((y^2-1))/((x^2-1)),y(0)=1 ?
The (dy)/(dx)=((y^2-1))/((x^2-1)),y(0)=1 is 0