What is area y=e^{3x},y=e^{7x},x=1 ?

The answer to area y=e^{3x},y=e^{7x},x=1 is (3e^7-7e^3+4)/(21)

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area y=e^{3x},y=e^{7x},x=1

area

y = e^{3 x}, y = e^{7 x}, x = 1

\frac{3 e ^{7} - 7 e ^{3} + 4}{21}

Decimal Notation

150.15717 \dots

Solution steps

Apply the area formula:

\int_{0}^{1} e^{3 x} - e^{7 x} d x

Solve

\int_{0}^{1} e^{3 x} - e^{7 x} d x : \frac{3 e ^{7} - 7 e ^{3} + 4}{21}

The area is:

= \frac{3 e ^{7} - 7 e ^{3} + 4}{21}

\int e^{2 x - 3} d x

\frac{d y}{d x} + \frac{y}{x} = \frac{3}{y}

\frac{d}{d x} (e^{x} (x - 2)^{2})

y = ln (a - 1)

\int \frac{x ^{2} + 6 x + 6}{x ^{3} + 9 x ^{2} + 18 x + 7} d x

What is area y=e^{3x},y=e^{7x},x=1 ?
The answer to area y=e^{3x},y=e^{7x},x=1 is (3e^7-7e^3+4)/(21)