What is the derivative of (ln(3)^x) ?

The derivative of (ln(3)^x) is ln(ln(3))ln^x(3)

What is the first derivative of (ln(3)^x) ?

The first derivative of (ln(3)^x) is ln(ln(3))ln^x(3)

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\frac{d}{d x} ((ln (3))^{x})

ln (ln (3)) ln^{x} (3)

Solution steps

\frac{d}{d x} ((ln (3))^{x})

Apply the derivative exponent rule:

\frac{d}{d x} (a^{x}) = a^{x} ln (a)

= (ln (3))^{x} ln (ln (3))

Simplify

= ln (ln (3)) ln^{x} (3)

x^{4} - 5 x^{2} + 4, at x = 1

\frac{d y}{d t} = 2 y - y^{2}

\int 1 - sin (2 x) d x

x, \frac{1}{18 x ^{2}}, \frac{x}{16}

\frac{d y}{d x} = 60 y x^{14}

What is the derivative of (ln(3)^x) ?
The derivative of (ln(3)^x) is ln(ln(3))ln^x(3)
What is the first derivative of (ln(3)^x) ?
The first derivative of (ln(3)^x) is ln(ln(3))ln^x(3)