What is the first derivative of 3x^2 ?

The first derivative of 3x^2 is 6x

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derivative of 3x^2

\frac{d}{d x} (3 x^{2})

6 x

Solution steps

\frac{d}{d x} (3 x^{2})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 3 \frac{d}{d x} (x^{2})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 3 \cdot 2 x^{2 - 1}

Simplify

= 6 x

f (x) = x - 5 sin (x), at x = \frac{π}{2}

x \to - 7 + lim (\frac{x + 6}{x + 7})

\int \frac{12}{x} d x

x \to 0 lim (\frac{1}{x})

\int \frac{x}{x ^{2} + 7} d x