What is the derivative of arccos(2x) ?

The derivative of arccos(2x) is -2/(sqrt(1-4x^2))

What is the first derivative of arccos(2x) ?

The first derivative of arccos(2x) is -2/(sqrt(1-4x^2))

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\frac{d}{d x} (arccos (2 x))

- \frac{2}{1 - 4 x ^{2}}

Solution steps

\frac{d}{d x} (arccos (2 x))

Apply the chain rule:

- \frac{1}{1 - ( 2 x ) ^{2}} \frac{d}{d x} (2 x)

= - \frac{1}{1 - ( 2 x ) ^{2}} \frac{d}{d x} (2 x)

\frac{d}{d x} (2 x) = 2

= - \frac{1}{1 - ( 2 x ) ^{2}} \cdot 2

Simplify

- \frac{1}{1 - ( 2 x ) ^{2}} \cdot 2 : - \frac{2}{1 - 4 x ^{2}}

= - \frac{2}{1 - 4 x ^{2}}

\frac{\partial}{\partial x} (12 x y e^{- x^{2} - y^{2}})

x \to 0 lim (3 x + 41)

\frac{\partial}{\partial y} (2 x^{3} + 4 y - 2 z^{2})

\frac{d}{d x} (\frac{x ^{2} - 3 x - 54}{x + 6})

f (x) = 5 - 2 x

What is the derivative of arccos(2x) ?
The derivative of arccos(2x) is -2/(sqrt(1-4x^2))
What is the first derivative of arccos(2x) ?
The first derivative of arccos(2x) is -2/(sqrt(1-4x^2))