What is the derivative of f(x)=(3x)/(e^x) ?

The derivative of f(x)=(3x)/(e^x) is (3(1-x))/(e^x)

What is the first derivative of f(x)=(3x)/(e^x) ?

The first derivative of f(x)=(3x)/(e^x) is (3(1-x))/(e^x)

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derivative of

f (x) = \frac{3 x}{e ^{x}}

\frac{3 ( 1 - x )}{e ^{x}}

Solution steps

\frac{d}{d x} (\frac{3 x}{e ^{x}})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 3 \frac{d}{d x} (\frac{x}{e ^{x}})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= 3 \cdot \frac{\frac{d x}{d x} e ^{x} - \frac{d}{d x} ( e ^{x} ) x}{( e ^{x} ) ^{2}}

\frac{d x}{d x} = 1

\frac{d}{d x} (e^{x}) = e^{x}

= 3 \cdot \frac{1 \cdot e ^{x} - e ^{x} x}{( e ^{x} ) ^{2}}

Simplify

3 \cdot \frac{1 \cdot e ^{x} - e ^{x} x}{( e ^{x} ) ^{2}} : \frac{3 ( 1 - x )}{e ^{x}}

= \frac{3 ( 1 - x )}{e ^{x}}

f (x) = 2 e^{x} + x, (0, 2)

\int (x + 3) (x - 1)^{5} d x

\frac{d x}{d t} = 4 x (7 - x)

f (x) = \frac{4}{3 x - 1}, at x = 1

x (x + 1) \cdot \frac{d y}{d x} + x y = 1

What is the derivative of f(x)=(3x)/(e^x) ?
The derivative of f(x)=(3x)/(e^x) is (3(1-x))/(e^x)
What is the first derivative of f(x)=(3x)/(e^x) ?
The first derivative of f(x)=(3x)/(e^x) is (3(1-x))/(e^x)