What is the derivative of ax^3+bx^2 ?

The derivative of ax^3+bx^2 is 3ax^2+2bx

What is the first derivative of ax^3+bx^2 ?

The first derivative of ax^3+bx^2 is 3ax^2+2bx

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\frac{d}{d x} (a x^{3} + b x^{2})

3 a x^{2} + 2 b x

Solution steps

\frac{d}{d x} (a x^{3} + b x^{2})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (a x^{3}) + \frac{d}{d x} (b x^{2})

\frac{d}{d x} (a x^{3}) = 3 a x^{2}

\frac{d}{d x} (b x^{2}) = 2 b x

= 3 a x^{2} + 2 b x

\frac{d}{d x} (\frac{- 3}{x + 1})

n = 1 \sum \infty \frac{n ^{8}}{n !}

\frac{d}{d x} (x^{3} - x^{2} - 6 x)

\frac{d}{d x} ((x^{- 2} + x)^{3})

y^{^{''}} - 4 y^{^{'}} - 5 y = 0, y (1) = 0, y^{^{'}} (1) = 2

What is the derivative of ax^3+bx^2 ?
The derivative of ax^3+bx^2 is 3ax^2+2bx
What is the first derivative of ax^3+bx^2 ?
The first derivative of ax^3+bx^2 is 3ax^2+2bx