What is the tangent of f(x)=7x-4x^2,(-1,-11) ?

The tangent of f(x)=7x-4x^2,(-1,-11) is y=15x+4

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tangent of f(x)=7x-4x^2,(-1,-11)

tangent of

f (x) = 7 x - 4 x^{2}, (- 1, - 11)

y = 15 x + 4

Solution steps

Find the slope of

f (x) = 7 x - 4 x^{2} : \frac{df ( x )}{d x} = 7 - 8 x

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 15

Find the line with slope m=

15

and passing through

(- 1, - 11) : y = 15 x + 4

y = 15 x + 4

f (x) = \frac{5}{x - 7}, (8, 5)

y = x^{16}

\frac{d y}{d x} = x - 2 y

\frac{x}{x}

\int \frac{e ^{6 x}}{e ^{6 x} + 5} d x

What is the tangent of f(x)=7x-4x^2,(-1,-11) ?
The tangent of f(x)=7x-4x^2,(-1,-11) is y=15x+4