What is the derivative of x^3+x-2 ?

The derivative of x^3+x-2 is 3x^2+1

What is the first derivative of x^3+x-2 ?

The first derivative of x^3+x-2 is 3x^2+1

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\frac{d}{d x} (x^{3} + x - 2)

3 x^{2} + 1

Solution steps

\frac{d}{d x} (x^{3} + x - 2)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{3}) + \frac{d x}{d x} - \frac{d}{d x} (2)

\frac{d}{d x} (x^{3}) = 3 x^{2}

\frac{d x}{d x} = 1

\frac{d}{d x} (2) = 0

= 3 x^{2} + 1 - 0

Simplify

= 3 x^{2} + 1

x \to 2 lim (\frac{5}{x} - 8)

\int - x^{2} + 2 x + 3 d x

\frac{d y}{d x} = 4 x^{3} y - 6 x^{2} y

{\frac{- 3}{- s + 2}}

\frac{d}{d x} (x^{2} y^{^{''}} - 9 x y + 25 y)

What is the derivative of x^3+x-2 ?
The derivative of x^3+x-2 is 3x^2+1
What is the first derivative of x^3+x-2 ?
The first derivative of x^3+x-2 is 3x^2+1