What is the derivative of 1/((x-1^2)) ?

The derivative of 1/((x-1^2)) is -2/((x-1)^3)

What is the first derivative of 1/((x-1^2)) ?

The first derivative of 1/((x-1^2)) is -2/((x-1)^3)

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\frac{d}{d x} (\frac{1}{( x - 1 ) ^{2}})

- \frac{2}{( x - 1 ) ^{3}}

Solution steps

\frac{d}{d x} (\frac{1}{( x - 1 ) ^{2}})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= \frac{d}{d x} ((x - 1)^{- 2})

Apply the chain rule:

- \frac{2}{( x - 1 ) ^{3}} \frac{d}{d x} (x - 1)

= - \frac{2}{( x - 1 ) ^{3}} \frac{d}{d x} (x - 1)

\frac{d}{d x} (x - 1) = 1

= - \frac{2}{( x - 1 ) ^{3}} \cdot 1

Simplify

= - \frac{2}{( x - 1 ) ^{3}}

\frac{4 x ^{2} + 2 x + 4}{x}

\frac{d y}{d x} = e^{4 x} + 5 y

x \to 0 lim (5 x^{4})

\int_{0}^{1} 7 x x^{2} + 16 d x

What is the derivative of 1/((x-1^2)) ?
The derivative of 1/((x-1^2)) is -2/((x-1)^3)
What is the first derivative of 1/((x-1^2)) ?
The first derivative of 1/((x-1^2)) is -2/((x-1)^3)