What is the derivative of f(x)=x^3-8x+2 ?

The derivative of f(x)=x^3-8x+2 is 3x^2-8

What is the first derivative of f(x)=x^3-8x+2 ?

The first derivative of f(x)=x^3-8x+2 is 3x^2-8

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derivative of

f (x) = x^{3} - 8 x + 2

3 x^{2} - 8

Solution steps

\frac{d}{d x} (x^{3} - 8 x + 2)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{3}) - \frac{d}{d x} (8 x) + \frac{d}{d x} (2)

\frac{d}{d x} (x^{3}) = 3 x^{2}

\frac{d}{d x} (8 x) = 8

\frac{d}{d x} (2) = 0

= 3 x^{2} - 8 + 0

Simplify

= 3 x^{2} - 8

\frac{d}{d x} (3 x^{2} + x + 4)

\int_{1}^{4} x^{- \frac{3}{2}} d x

\int_{0}^{4} \frac{5 π y ^{4}}{4} d y

\frac{d y}{d x} + y cos (x) = 3 cos (x)

\int \frac{x cos ( x ^{2} )}{sin ( x ^{2} )} d x

What is the derivative of f(x)=x^3-8x+2 ?
The derivative of f(x)=x^3-8x+2 is 3x^2-8
What is the first derivative of f(x)=x^3-8x+2 ?
The first derivative of f(x)=x^3-8x+2 is 3x^2-8