What is the derivative of sin(1/x) ?

The derivative of sin(1/x) is -(cos(1/x))/(x^2)

What is the first derivative of sin(1/x) ?

The first derivative of sin(1/x) is -(cos(1/x))/(x^2)

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derivative of

sin (\frac{1}{x})

- \frac{cos ( \frac{1}{x} )}{x ^{2}}

Solution steps

\frac{d}{d x} (sin (\frac{1}{x}))

Apply the chain rule:

cos (\frac{1}{x}) \frac{d}{d x} (\frac{1}{x})

= cos (\frac{1}{x}) \frac{d}{d x} (\frac{1}{x})

\frac{d}{d x} (\frac{1}{x}) = - \frac{1}{x ^{2}}

= cos (\frac{1}{x}) (- \frac{1}{x ^{2}})

Simplify

cos (\frac{1}{x}) (- \frac{1}{x ^{2}}) : - \frac{cos ( \frac{1}{x} )}{x ^{2}}

= - \frac{cos ( \frac{1}{x} )}{x ^{2}}

\int x + 6 d x

y = x, y = 2 x, y = - x + 4

x \to 1 lim (2 (0.9) + 1)

\frac{\partial}{\partial x} (- 3 e^{- 3 x})

n = 1 \sum \infty \frac{1}{1.0 5 ^{n}} \cdot 1

What is the derivative of sin(1/x) ?
The derivative of sin(1/x) is -(cos(1/x))/(x^2)
What is the first derivative of sin(1/x) ?
The first derivative of sin(1/x) is -(cos(1/x))/(x^2)