What is (\partial)/(\partial x)(-3e^{-3x}) ?

The answer to (\partial)/(\partial x)(-3e^{-3x}) is 9e^{-3x}

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(\partial)/(\partial x)(-3e^{-3x})

\frac{\partial}{\partial x} (- 3 e^{- 3 x})

9 e^{- 3 x}

Solution steps

\frac{\partial}{\partial x} (- 3 e^{- 3 x})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - 3 \frac{\partial}{\partial x} (e^{- 3 x})

Apply the chain rule:

e^{- 3 x} \frac{\partial}{\partial x} (- 3 x)

= e^{- 3 x} \frac{\partial}{\partial x} (- 3 x)

\frac{\partial}{\partial x} (- 3 x) = - 3

= - 3 e^{- 3 x} (- 3)

Simplify

= 9 e^{- 3 x}

n = 1 \sum \infty \frac{1}{1.0 5 ^{n}} \cdot 1

\int_{6}^{\infty} x e^{- 5 x} d x

\frac{d}{d x} (2 ln (3 x^{2} - 1))

\frac{d}{d x} (- 19 x^{2} + 4 x + 22)

g (x) = x^{5} - 2 x

What is (\partial)/(\partial x)(-3e^{-3x}) ?
The answer to (\partial)/(\partial x)(-3e^{-3x}) is 9e^{-3x}