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Popular >

xy+y^2-x^2y^'=0

Solution

x y + y^{2} - x^{2} y^{^{'}} = 0

Solution

y = \frac{x}{- ln ( x ) + c _{1}}

Solution steps

x y + y^{2} - x^{2} y^{'} (x) = 0

Solve Bernoulli ODE:

y = \frac{x}{- ln ( x ) + c _{1}}

y = \frac{x}{- ln ( x ) + c _{1}}

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Frequently Asked Questions (FAQ)

What is the solution for xy+y^2-x^2y^'=0 ?
The solution for xy+y^2-x^2y^'=0 is y= x/(-ln(x)+c_{1)}