What is the solution for 2y^{''}-3y^'-14y=0 ?

The solution for 2y^{''}-3y^'-14y=0 is y=c_{1}e^{(7t)/2}+c_{2}e^{-2t}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2y^{''}-3y^'-14y=0

2 y^{^{''}} - 3 y^{^{'}} - 14 y = 0

y = c_{1} e^{\frac{7 t}{2}} + c_{2} e^{- 2 t}

Solution steps

2 y^{''} (t) - 3 y^{'} (t) - 14 y = 0

Solve linear ODE:

y = c_{1} e^{\frac{7 t}{2}} + c_{2} e^{- 2 t}

y = c_{1} e^{\frac{7 t}{2}} + c_{2} e^{- 2 t}

\frac{d y}{d x} = 0.15 y + 200

(- x)^{^{'}}

\frac{d}{d x} (ln (arcsin (x)))

\int (\frac{- x ^{2} + x}{x ^{4}}) d x

\int 2 x - 2 x^{2} d x

What is the solution for 2y^{''}-3y^'-14y=0 ?
The solution for 2y^{''}-3y^'-14y=0 is y=c_{1}e^{(7t)/2}+c_{2}e^{-2t}