What is the derivative of tsin(t)+cos(t) ?

The derivative of tsin(t)+cos(t) is tcos(t)

What is the first derivative of tsin(t)+cos(t) ?

The first derivative of tsin(t)+cos(t) is tcos(t)

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derivative of

t sin (t) + cos (t)

t cos (t)

Solution steps

\frac{d}{d t} (t sin (t) + cos (t))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d t} (t sin (t)) + \frac{d}{d t} (cos (t))

\frac{d}{d t} (t sin (t)) = sin (t) + t cos (t)

\frac{d}{d t} (cos (t)) = - sin (t)

= sin (t) + t cos (t) - sin (t)

Simplify

= t cos (t)

2 t^{2} \frac{d x}{d t} = 3 t x + x^{2}

y = \frac{5}{4 x ^{3}}

x \to 0 - lim (x^{2})

\frac{d N}{d t} + N = Nt e^{t + 5}

x \to 0 lim (x - 3)

What is the derivative of tsin(t)+cos(t) ?
The derivative of tsin(t)+cos(t) is tcos(t)
What is the first derivative of tsin(t)+cos(t) ?
The first derivative of tsin(t)+cos(t) is tcos(t)