What is the derivative of y= 5/(4x^3) ?

The derivative of y= 5/(4x^3) is -(15)/(4x^4)

What is the first derivative of y= 5/(4x^3) ?

The first derivative of y= 5/(4x^3) is -(15)/(4x^4)

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derivative of

y = \frac{5}{4 x ^{3}}

- \frac{15}{4 x ^{4}}

Solution steps

\frac{d}{d x} (\frac{5}{4 x ^{3}})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{5}{4} \frac{d}{d x} (\frac{1}{x ^{3}})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= \frac{5}{4} \frac{d}{d x} (x^{- 3})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= \frac{5}{4} (- 3 x^{- 3 - 1})

Simplify

\frac{5}{4} (- 3 x^{- 3 - 1}) : - \frac{15}{4 x ^{4}}

= - \frac{15}{4 x ^{4}}

x \to 0 - lim (x^{2})

\frac{d N}{d t} + N = Nt e^{t + 5}

x \to 0 lim (x - 3)

t \to 0 lim (3 t^{2})

\frac{d}{d x} (2 (x - π))

What is the derivative of y= 5/(4x^3) ?
The derivative of y= 5/(4x^3) is -(15)/(4x^4)
What is the first derivative of y= 5/(4x^3) ?
The first derivative of y= 5/(4x^3) is -(15)/(4x^4)