What is the derivative of ln(8-3x) ?

The derivative of ln(8-3x) is -3/(8-3x)

What is the first derivative of ln(8-3x) ?

The first derivative of ln(8-3x) is -3/(8-3x)

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\frac{d}{d x} (ln (8 - 3 x))

- \frac{3}{8 - 3 x}

Solution steps

\frac{d}{d x} (ln (8 - 3 x))

Apply the chain rule:

\frac{1}{8 - 3 x} \frac{d}{d x} (8 - 3 x)

= \frac{1}{8 - 3 x} \frac{d}{d x} (8 - 3 x)

\frac{d}{d x} (8 - 3 x) = - 3

= \frac{1}{8 - 3 x} (- 3)

Simplify

\frac{1}{8 - 3 x} (- 3) : - \frac{3}{8 - 3 x}

= - \frac{3}{8 - 3 x}

(x^{2} - 8 x)^{4}

\frac{d}{d x} (\frac{e ^{x} x - e ^{x}}{x ^{2}})

y = 2^{x}, y = 4^{x}, y = 4

\frac{\partial}{\partial x} (sin (5 x^{4} y - 3 x y^{4}))

\frac{\partial}{\partial y} ((x^{2} + x y)^{3})

What is the derivative of ln(8-3x) ?
The derivative of ln(8-3x) is -3/(8-3x)
What is the first derivative of ln(8-3x) ?
The first derivative of ln(8-3x) is -3/(8-3x)