What is the derivative of (x^2-8x)^4 ?

The derivative of (x^2-8x)^4 is 4(x^2-8x)^3(2x-8)

What is the first derivative of (x^2-8x)^4 ?

The first derivative of (x^2-8x)^4 is 4(x^2-8x)^3(2x-8)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

derivative of

(x^{2} - 8 x)^{4}

4 (x^{2} - 8 x)^{3} (2 x - 8)

Solution steps

\frac{d}{d x} ((x^{2} - 8 x)^{4})

Apply the chain rule:

4 (x^{2} - 8 x)^{3} \frac{d}{d x} (x^{2} - 8 x)

= 4 (x^{2} - 8 x)^{3} \frac{d}{d x} (x^{2} - 8 x)

\frac{d}{d x} (x^{2} - 8 x) = 2 x - 8

= 4 (x^{2} - 8 x)^{3} (2 x - 8)

\frac{d}{d x} (\frac{e ^{x} x - e ^{x}}{x ^{2}})

y = 2^{x}, y = 4^{x}, y = 4

\frac{\partial}{\partial x} (sin (5 x^{4} y - 3 x y^{4}))

\frac{\partial}{\partial y} ((x^{2} + x y)^{3})

3 y^{^{'}} - 2 y = e^{- \frac{π t}{2}}

What is the derivative of (x^2-8x)^4 ?
The derivative of (x^2-8x)^4 is 4(x^2-8x)^3(2x-8)
What is the first derivative of (x^2-8x)^4 ?
The first derivative of (x^2-8x)^4 is 4(x^2-8x)^3(2x-8)