What is the derivative of 3x^2-12x+9 ?

The derivative of 3x^2-12x+9 is 6x-12

What is the first derivative of 3x^2-12x+9 ?

The first derivative of 3x^2-12x+9 is 6x-12

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\frac{d}{d x} (3 x^{2} - 12 x + 9)

6 x - 12

Solution steps

\frac{d}{d x} (3 x^{2} - 12 x + 9)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 x^{2}) - \frac{d}{d x} (12 x) + \frac{d}{d x} (9)

\frac{d}{d x} (3 x^{2}) = 6 x

\frac{d}{d x} (12 x) = 12

\frac{d}{d x} (9) = 0

= 6 x - 12 + 0

Simplify

= 6 x - 12

11 t^{2} y^{^{''}} - 22 y = 9 t^{2} - 9

x \to 0 lim (cos (2 - 2 e^{x}))

x \to 1 lim (2)

x \to 6 - lim (tan (\frac{π x}{4}))

\int \frac{1}{x ( x ^{3} + 1 )} d x

What is the derivative of 3x^2-12x+9 ?
The derivative of 3x^2-12x+9 is 6x-12
What is the first derivative of 3x^2-12x+9 ?
The first derivative of 3x^2-12x+9 is 6x-12