What is the derivative of ln(x^3+4) ?

The derivative of ln(x^3+4) is (3x^2)/(x^3+4)

What is the first derivative of ln(x^3+4) ?

The first derivative of ln(x^3+4) is (3x^2)/(x^3+4)

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\frac{d}{d x} (ln (x^{3} + 4))

\frac{3 x ^{2}}{x ^{3} + 4}

Solution steps

\frac{d}{d x} (ln (x^{3} + 4))

Apply the chain rule:

\frac{1}{x ^{3} + 4} \frac{d}{d x} (x^{3} + 4)

= \frac{1}{x ^{3} + 4} \frac{d}{d x} (x^{3} + 4)

\frac{d}{d x} (x^{3} + 4) = 3 x^{2}

= \frac{1}{x ^{3} + 4} \cdot 3 x^{2}

Simplify

\frac{1}{x ^{3} + 4} \cdot 3 x^{2} : \frac{3 x ^{2}}{x ^{3} + 4}

= \frac{3 x ^{2}}{x ^{3} + 4}

h (x) = ln (\frac{x ^{2} - 1}{x ^{2} + 1})

y^{^{'}} = 2 cos (5 x)

y^{^{''}} + 3 y^{^{'}} + 2 y = x^{2}

\frac{d}{d x} (\frac{- 2}{x x})

\frac{d}{d x} ((3 x)^{\frac{1}{2}})

What is the derivative of ln(x^3+4) ?
The derivative of ln(x^3+4) is (3x^2)/(x^3+4)
What is the first derivative of ln(x^3+4) ?
The first derivative of ln(x^3+4) is (3x^2)/(x^3+4)