What is the first derivative of 1x^2 ?

The first derivative of 1x^2 is 2x

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derivative of 1x^2

\frac{d}{d x} (1 x^{2})

2 x

Solution steps

\frac{d}{d x} (1 \cdot x^{2})

Simplify

1 \cdot x^{2} : x^{2}

= \frac{d}{d x} (x^{2})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 2 x^{2 - 1}

Simplify

= 2 x

\int x^{3} (x^{2} + 1) d x

\frac{d}{d x} ((x - 3)^{2})

\int_{1}^{2} sin (x) d x

\frac{d}{d x} ((x^{2} - 4)^{2})

\frac{d y}{d x} = sin (3 x) - cos (5 x)