What is the derivative of 7-3x^2 ?

The derivative of 7-3x^2 is -6x

What is the first derivative of 7-3x^2 ?

The first derivative of 7-3x^2 is -6x

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\frac{d}{d x} (7 - 3 x^{2})

- 6 x

Solution steps

\frac{d}{d x} (7 - 3 x^{2})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (7) - \frac{d}{d x} (3 x^{2})

\frac{d}{d x} (7) = 0

\frac{d}{d x} (3 x^{2}) = 6 x

= 0 - 6 x

Simplify

= - 6 x

\frac{\partial}{\partial y} (x^{2} y^{2} z^{2})

\int \frac{ln ( x )}{x ( ln ^{2} ( x ) + 4 )} d x

y^{^{''}} + 36 y = 12 sin (6 t)

\frac{d y}{d x} = \frac{x - 3}{y - 3}

\int \frac{1}{4 x + 5 x} d x