What is the derivative of 9/(x^3+1/x) ?

The derivative of 9/(x^3+1/x) is -(27)/(x^4)-1/(x^2)

What is the first derivative of 9/(x^3+1/x) ?

The first derivative of 9/(x^3+1/x) is -(27)/(x^4)-1/(x^2)

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\frac{d}{d x} (\frac{9}{x ^{3}} + \frac{1}{x})

- \frac{27}{x ^{4}} - \frac{1}{x ^{2}}

Solution steps

\frac{d}{d x} (\frac{9}{x ^{3}} + \frac{1}{x})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (\frac{9}{x ^{3}}) + \frac{d}{d x} (\frac{1}{x})

\frac{d}{d x} (\frac{9}{x ^{3}}) = - \frac{27}{x ^{4}}

\frac{d}{d x} (\frac{1}{x}) = - \frac{1}{x ^{2}}

= - \frac{27}{x ^{4}} - \frac{1}{x ^{2}}

\int_{0}^{1} (x^{3})^{2} d x

\frac{d y}{d x}, e^{x} y = 5

y = \frac{4 x}{x + 2}

\frac{\partial}{\partial x} (e^{s i n (x + c t)})

What is the derivative of 9/(x^3+1/x) ?
The derivative of 9/(x^3+1/x) is -(27)/(x^4)-1/(x^2)
What is the first derivative of 9/(x^3+1/x) ?
The first derivative of 9/(x^3+1/x) is -(27)/(x^4)-1/(x^2)