What is the integral of 1/(x^{5/2)} ?

The integral of 1/(x^{5/2)} is -2/(3x^{3/2)}+C

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integral of 1/(x^{5/2)}

\int \frac{1}{x ^{\frac{5}{2}}} d x

- \frac{2}{3 x ^{\frac{3}{2}}} + C

Solution steps

\int \frac{1}{x ^{\frac{5}{2}}} d x

Apply the Power Rule

: - \frac{2}{3 x ^{\frac{3}{2}}}

= - \frac{2}{3 x ^{\frac{3}{2}}}

Add a constant to the solution

= - \frac{2}{3 x ^{\frac{3}{2}}} + C

\frac{d}{d x} (3 arcsin (x) + 3 x arcsech (x))

\int \frac{24 x ^{3} - 6}{2 x ^{4} - 2 x + 3} d x

x \to 0 lim (5 - x^{2})

x \to 1 + lim (\frac{9}{x ^{3} - 1})

- 5 x^{2} + 3 y^{2} = 1

What is the integral of 1/(x^{5/2)} ?
The integral of 1/(x^{5/2)} is -2/(3x^{3/2)}+C