What is the derivative of f(x)=3x+8/(x^3) ?

The derivative of f(x)=3x+8/(x^3) is 3-(24)/(x^4)

What is the first derivative of f(x)=3x+8/(x^3) ?

The first derivative of f(x)=3x+8/(x^3) is 3-(24)/(x^4)

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derivative of

f (x) = 3 x + \frac{8}{x ^{3}}

3 - \frac{24}{x ^{4}}

Solution steps

\frac{d}{d x} (3 x + \frac{8}{x ^{3}})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 x) + \frac{d}{d x} (\frac{8}{x ^{3}})

\frac{d}{d x} (3 x) = 3

\frac{d}{d x} (\frac{8}{x ^{3}}) = - \frac{24}{x ^{4}}

= 3 - \frac{24}{x ^{4}}

n = 0 \sum \infty n + (- 1)^{n}

\frac{e ^{x} + e ^{- x}}{e ^{2 x}}

(2 x^{4})^{^{'}}

x \to 0 + lim (\frac{ln ( x )}{1})

f (x) = x e^{2 x}

What is the derivative of f(x)=3x+8/(x^3) ?
The derivative of f(x)=3x+8/(x^3) is 3-(24)/(x^4)
What is the first derivative of f(x)=3x+8/(x^3) ?
The first derivative of f(x)=3x+8/(x^3) is 3-(24)/(x^4)