What is the limit as x approaches 0+of (ln(x))/1 ?

The limit as x approaches 0+of (ln(x))/1 is -infinity

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limit as x approaches 0+of (ln(x))/1

x \to 0 + lim (\frac{ln ( x )}{1})

- \infty

Solution steps

x \to 0 + lim (\frac{ln ( x )}{1})

x \to a lim [\frac{f ( x )}{g ( x )}] = \frac{lim _{x \to a} f ( x )}{lim _{x \to a} g ( x )}, x \to a lim g (x) \neq = 0

With the exception of indeterminate form

= \frac{lim _{x \to 0 +} ( ln ( x ) )}{lim _{x \to 0 +} ( 1 )}

x \to 0 + lim (ln (x)) = - \infty

x \to 0 + lim (1) = 1

= \frac{- \infty}{1}

Apply Infinity Property:

\frac{- \infty}{c} = - \infty

= - \infty

f (x) = x e^{2 x}

\int (2 x - 1) sin (4 x y) d x

\frac{2}{t ^{4}}

n = 1 \sum \infty \frac{( 1 )}{2 n + 7}

n = 2 \sum \infty 1 - \frac{1}{n ^{2}}

What is the limit as x approaches 0+of (ln(x))/1 ?
The limit as x approaches 0+of (ln(x))/1 is -infinity