What is the sum from n=2 to infinity of 1-1/(n^2) ?

The sum from n=2 to infinity of 1-1/(n^2) is diverges

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sum from n=2 to infinity of 1-1/(n^2)

n = 2 \sum \infty 1 - \frac{1}{n ^{2}}

diverges

Solution steps

n = 2 \sum \infty 1 - \frac{1}{n ^{2}}

Apply Series Divergence Test:

diverges

= diverges

y = x^{4} ln (x)

x \frac{d y}{d x} - 4 y = x^{6} x^{x}

\int 50 + 3.5 x e^{- 0.01 x^{2}} d x

y^{^{'}} = x e^{x^{2} - y}

y^{^{'}} = \frac{( 3 x ^{6} e ^{\frac{y}{x}} + x ^{4} y ^{2} )}{x ^{5} y}

What is the sum from n=2 to infinity of 1-1/(n^2) ?
The sum from n=2 to infinity of 1-1/(n^2) is diverges