What is the limit as x approaches 0 of 1/(2x^3) ?

The limit as x approaches 0 of 1/(2x^3) is diverges

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limit as x approaches 0 of 1/(2x^3)

x \to 0 lim (\frac{1}{2 x ^{3}})

diverges

Solution steps

x \to 0 lim (\frac{1}{2 x ^{3}})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 0 + lim (\frac{1}{2 x ^{3}}) = \infty

x \to 0 - lim (\frac{1}{2 x ^{3}}) = - \infty

= diverges

y = \frac{4 x ^{2} + 6 x}{3 x ^{3} + 2}

x \to \infty lim ((\frac{( e ^{x} - e ^{- x} )}{( e ^{x} + e ^{- x} )}) + 4)

\int (5 cos (x) - 4, x) d x

x \to \infty lim (\frac{2 - x}{x + 1} + \frac{2 ^{- x} \cdot x}{x + 2})

y^{^{'}} = 2 y (1 - \frac{y}{6200})

What is the limit as x approaches 0 of 1/(2x^3) ?
The limit as x approaches 0 of 1/(2x^3) is diverges