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Popular >

integral from 0 to 2 of (x^2-4)

Solution

\int_{0}^{2} (x^{2} - 4) d x

Solution

- \frac{16}{3}

+1

Decimal Notation

- 5.33333 \dots

Solution steps

\int_{0}^{2} x^{2} - 4 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{2} x^{2} d x - \int_{0}^{2} 4 d x

\int_{0}^{2} x^{2} d x = \frac{8}{3}

\int_{0}^{2} 4 d x = 8

= \frac{8}{3} - 8

Simplify

\frac{8}{3} - 8 : - \frac{16}{3}

= - \frac{16}{3}

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Frequently Asked Questions (FAQ)

What is the integral from 0 to 2 of (x^2-4) ?
The integral from 0 to 2 of (x^2-4) is -16/3