What is the first derivative of 7e^u ?

The first derivative of 7e^u is 7e^u

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derivative of 7e^u

derivative of

7 e^{u}

7 e^{u}

Solution steps

\frac{d}{d u} (7 e^{u})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 7 \frac{d}{d u} (e^{u})

Apply the common derivative:

\frac{d}{d u} (e^{u}) = e^{u}

= 7 e^{u}

\frac{d}{d x} (7^{3^{x^{2}}})

4 + 7 cos (5 t)

\int \frac{6}{( 1 - x ^{2} ) ^{\frac{3}{2}}} d x

\frac{d y}{( 5 - 3 y ) ^{2}} = \frac{d x}{2 ( 4 - x ) ^{2}}

f^{^{'}} (x) = x e^{- x^{2}}