What is the derivative of e^{x^4+x} ?

The derivative of e^{x^4+x} is e^{x^4+x}(4x^3+1)

What is the first derivative of e^{x^4+x} ?

The first derivative of e^{x^4+x} is e^{x^4+x}(4x^3+1)

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\frac{d}{d x} (e^{x^{4} + x})

e^{x^{4} + x} (4 x^{3} + 1)

Solution steps

\frac{d}{d x} (e^{x^{4} + x})

Apply the chain rule:

e^{x^{4} + x} \frac{d}{d x} (x^{4} + x)

= e^{x^{4} + x} \frac{d}{d x} (x^{4} + x)

\frac{d}{d x} (x^{4} + x) = 4 x^{3} + 1

= e^{x^{4} + x} (4 x^{3} + 1)

x^{2} + 3 x + 5

\frac{\partial}{\partial y} (x + 6 y)

\int x^{2} + 3 e^{x} + C d x

\frac{1}{1 - \frac{1}{1 - x}}

\frac{\partial}{\partial y} (tan (5 + 2 x^{2} y^{4} z^{2}))

What is the derivative of e^{x^4+x} ?
The derivative of e^{x^4+x} is e^{x^4+x}(4x^3+1)
What is the first derivative of e^{x^4+x} ?
The first derivative of e^{x^4+x} is e^{x^4+x}(4x^3+1)