What is the limit as z approaches-1+2i of z/(z+1+2i) ?

The limit as z approaches-1+2i of z/(z+1+2i) is 1/2+i 1/4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

limit as z approaches-1+2i of z/(z+1+2i)

z \to - 1 + 2 i lim (\frac{z}{z + 1 + 2 i})

\frac{1}{2} + i \frac{1}{4}

Solution steps

z \to - 1 + 2 i lim (\frac{z}{z + 1 + 2 i})

Plug in the value

z = - 1 + 2 i

= \frac{- 1 + 2 i}{- 1 + 2 i + 1 + 2 i}

Simplify

\frac{- 1 + 2 i}{- 1 + 2 i + 1 + 2 i} : \frac{1}{2} + i \frac{1}{4}

= \frac{1}{2} + i \frac{1}{4}

\frac{d}{d x} (- \frac{x ^{2}}{y ^{2}})

m \to 0 lim (\frac{m}{m ^{2} + 4 m})

\int e^{4 x - 3} d x

\int \frac{( x - 1 )}{( x - 2 ) ( x - 3 )} d x

x \to 2 lim (∣ x ∣)

What is the limit as z approaches-1+2i of z/(z+1+2i) ?
The limit as z approaches-1+2i of z/(z+1+2i) is 1/2+i 1/4