What is the solution for x(dy)/(dx)=y+sqrt(x^2-y^2),x>0 ?

The solution for x(dy)/(dx)=y+sqrt(x^2-y^2),x>0 is y=sin(ln(x)+c_{1})x

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x(dy)/(dx)=y+sqrt(x^2-y^2),x>0

x \frac{d y}{d x} = y + x^{2} - y^{2}, x > 0

y = sin (ln (x) + c_{1}) x

Solution steps

x \frac{d y}{d x} = y + x^{2} - y^{2}

Solve using substitution:

y = sin (ln (x) + c_{1}) x

y = sin (ln (x) + c_{1}) x

x = 2 + y + 3, x = 2 - y + 3, x = y - 1

\frac{d}{d x} ((- 3 x^{5} + 1)^{3})

\int \frac{x}{( sin ( x ^{2} ) ) ^{2}} d x

\frac{\partial}{\partial x} (y + x cos (t))

\frac{\partial}{\partial x} (tan (2 x + y))

What is the solution for x(dy)/(dx)=y+sqrt(x^2-y^2),x>0 ?
The solution for x(dy)/(dx)=y+sqrt(x^2-y^2),x>0 is y=sin(ln(x)+c_{1})x