What is the tangent of f(x)=(x^3-25x)^{14},(5,0) ?

The tangent of f(x)=(x^3-25x)^{14},(5,0) is y=0

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tangent of f(x)=(x^3-25x)^{14},(5,0)

tangent of

f (x) = (x^{3} - 25 x)^{14}, (5, 0)

y = 0

Solution steps

Find the slope of

f (x) = (x^{3} - 25 x)^{14} : \frac{df ( x )}{d x} = 14 (x^{3} - 25 x)^{13} (3 x^{2} - 25)

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 0

Find the line with slope m=

0

and passing through

(5, 0) : y = 0

y = 0

t \to 0 lim (ln (sin (4 t)))

\frac{\partial}{\partial x} (e^{\frac{2 x + 3 y}{3 y}})

\frac{d}{d x} (5 (e^{x})^{- 4})

x \to 2 lim (12 x^{2})

x \to - 2 lim (\frac{∣ x + 2 ∣}{x + 2})

What is the tangent of f(x)=(x^3-25x)^{14},(5,0) ?
The tangent of f(x)=(x^3-25x)^{14},(5,0) is y=0