What is the derivative of f(x)=ln(4x+7) ?

The derivative of f(x)=ln(4x+7) is 4/(4x+7)

What is the first derivative of f(x)=ln(4x+7) ?

The first derivative of f(x)=ln(4x+7) is 4/(4x+7)

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derivative of

f (x) = ln (4 x + 7)

\frac{4}{4 x + 7}

Solution steps

\frac{d}{d x} (ln (4 x + 7))

Apply the chain rule:

\frac{1}{4 x + 7} \frac{d}{d x} (4 x + 7)

= \frac{1}{4 x + 7} \frac{d}{d x} (4 x + 7)

\frac{d}{d x} (4 x + 7) = 4

= \frac{1}{4 x + 7} \cdot 4

Simplify

\frac{1}{4 x + 7} \cdot 4 : \frac{4}{4 x + 7}

= \frac{4}{4 x + 7}

\frac{d}{d t} (sin (3 t))

\frac{d}{d x} (y z (x))

\int 4 x^{3} + 2 x y^{2} d x

\frac{\partial}{\partial x} (x^{\frac{1}{2}} y^{\frac{1}{3}})

4^{x}

What is the derivative of f(x)=ln(4x+7) ?
The derivative of f(x)=ln(4x+7) is 4/(4x+7)
What is the first derivative of f(x)=ln(4x+7) ?
The first derivative of f(x)=ln(4x+7) is 4/(4x+7)